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Shaft Diameter Calculator

Minimum shaft diameter for combined bending and torsion by the DE-Goodman fatigue criterion.

Find the minimum diameter of a rotating or stationary shaft carrying bending, torque and axial force. The calculator follows the distortion energy (DE) Goodman method from Shigley, with Marin surface, size and reliability factors and Neuber notch sensitivity for shoulders and keyways.

  • Live results
  • Full step-by-step working
  • PASS / FAIL checks
  • Free PDF report

Inputs

Shoulder r/d ≈ 0.1: 1.7; keyway: 2.1; plain: 1.0

Results

Minimum diameter
36.28 mm
Selected standard diameter
40 mm
Fatigue safety nf
2.66
PASS
Yield safety ny
5.81
PASS
Step-by-step calculation (12 steps)
  1. 1Unmodified endurance limit
    FormulaSe' = 0.5·Sut (Sut ≤ 1400 MPa)
    SolutionSe' = 0.5 × 700
    ResultSe' = 350 MPa
  2. 2Surface factor (Marin)
    Formulaka = a·Sut^b
    Solutionka = 4.51 × 700^(-0.265) [Machined / cold drawn]
    Resultka = 0.795
  3. 3Size factor (iterated with d)
    Formulakb = 1.24·d^(−0.107) (2.79 ≤ d ≤ 51 mm); 1.51·d^(−0.157) (51 < d ≤ 254 mm)
    Solutiond = 36.28 mm
    Resultkb = 0.844
  4. 4Reliability factor
    Formulake at 90% reliability
    Solutionkc = 1 (combined loading, von Mises), kd = 1 (room temperature)
    Resultke = 0.897
  5. 5Corrected endurance limit
    FormulaSe = ka·kb·kc·kd·ke·Se'
    SolutionSe = 0.795 × 0.844 × 1 × 1 × 0.897 × 350
    ResultSe = 210.7 MPa
  6. 6Fatigue stress concentration (Neuber)
    Formulaq = 1 / (1 + √a / √r), Kf = 1 + q·(Kt − 1)
    Solution√a = 0.307 √mm (bending), 0.234 √mm (torsion); q = 0.765, qs = 0.811
    ResultKf = 1.54, Kfs = 1.41
  7. 7Load components
    FormulaMa, Mm, Ta, Tm from shaft condition and torque type
    SolutionRotating shaft: bending fully reversed. Torque steady.
    ResultMa = 250, Mm = 0, Ta = 0, Tm = 300 N·m
  8. 8Minimum diameter (DE-Goodman)
    Formulad = { (16n/π)·[ √(4(Kf·Ma)² + 3(Kfs·Ta)²) / Se + √(4(Kf·Mm)² + 3(Kfs·Tm)²) / Sut ] }^(1/3)
    Solutiond = { (16 × 2 / π) × [ 767698 / 210.7 + 730199 / 700 ] }^(1/3) [moments in N·mm]
    Resultdmin = 36.28 mm
  9. 9Standard diameter (ISO 15 bearing bore series)
    Formulad ≥ dmin, next standard size
    Solution36.28 mm → next size
    Resultd = 40 mm
  10. 10Von Mises stresses at selected diameter
    Formulaσa′ = √(σa² + 3τa²), σm′ = √(σm² + 3τm²)
    Solutionσa = 61.09, τa = 0, σm = 0, τm = 33.55 MPa
    Resultσa′ = 61.09 MPa, σm′ = 58.11 MPa
  11. 11Fatigue safety factor (Goodman)
    Formulanf = 1 / (σa′/Se + σm′/Sut)
    Solutionnf = 1 / (61.09 / 208.5 + 58.11 / 700) [kb = 0.836 at d = 40]
    Resultnf = 2.66 ≥ 2PASS
  12. 12First-cycle yield check
    Formulany = Sy / √((σa + σm)² + 3(τa + τm)²)
    Solutionny = 490 / 84.31
    Resultny = 5.81 ≥ 2PASS

Engineering takeaways

  • Shaft size is driven by the alternating bending stress at the notch. Reducing Kt (larger fillet radius, relief groove) is often cheaper than a bigger diameter.
  • Check shaft deflection and slope at bearings and gears separately. Stiffness often governs over strength.
  • Check every critical section (shoulders, keyways, grooves). The worst section is not always at maximum moment.

Method: Shigley, Mechanical Engineering Design, DE-Goodman criterion with Marin factors and Neuber notch sensitivity.

The PDF report contains every input, formula, substitution and check shown above, in LTM calculation-sheet format.

Worked Example

The calculator selects the next standard diameter from the ISO 15 bearing bore series, then verifies fatigue and first-cycle yield safety factors at that size. Materials include E250, EN8, C45, EN19 / 42CrMo4 and EN24.

The calculator above opens with this example. Change any input to run your own case.

Inputs

Bending moment M (at critical section)250 N·m
Torque T300 N·m
Axial force Fa (0 if none)0 N
Shaft conditionRotating (bending fully reversed)
Torque typeSteady
MaterialC45 / CK45 Q&T (EN 10083-2) (Sut 700, Sy 490 MPa)
Surface finishMachined / cold drawn
Reliability90% (ke = 0.897)
Stress concentration Kt (bending)1.7
Stress concentration Kts (torsion)1.5
Notch radius r1 mm
Design factor of safety n2

Results

Minimum diameter36.28 mm
Selected standard diameter40 mm
Fatigue safety nf2.66 PASS
Yield safety ny5.81 PASS

Shaft Diameter Formulas Used

Corrected endurance limit

Se=ka kb kc kd ke Se′,Se′=0.5 SutS_e = k_a\,k_b\,k_c\,k_d\,k_e\,S_e',\qquad S_e' = 0.5\,S_{ut}
  • kasurface factor a·Sut^b
  • kbsize factor 1.24·d^-0.107
  • kereliability factor

Fatigue stress concentration

Kf=1+q (Kt−1),q=11+a/rK_f = 1 + q\,(K_t - 1),\qquad q = \frac{1}{1 + \sqrt{a}/\sqrt{r}}
  • Ktgeometric stress concentration
  • rnotch radius

DE-Goodman diameter

d={16nπ[4(KfMa)2+3(KfsTa)2Se+4(KfMm)2+3(KfsTm)2Sut]}1/3d = \left\{\frac{16n}{\pi}\left[\frac{\sqrt{4(K_f M_a)^2 + 3(K_{fs} T_a)^2}}{S_e} + \frac{\sqrt{4(K_f M_m)^2 + 3(K_{fs} T_m)^2}}{S_{ut}}\right]\right\}^{1/3}
  • Ma, Mmalternating and mean bending moment
  • Ta, Tmalternating and mean torque
  • ndesign factor

Yield check

ny=Sy(σa+σm)2+3(τa+τm)2n_y = \frac{S_y}{\sqrt{(\sigma_a + \sigma_m)^2 + 3(\tau_a + \tau_m)^2}}

Basis: Shigley DE-Goodman criterion; Marin factors; Neuber notch sensitivity. Results are for preliminary design and should be confirmed against supplier data and the governing standard.

Shaft Diameter Calculator FAQ

Why is bending treated as fully reversed on a rotating shaft?

A point on the surface of a rotating shaft passes from the tension side to the compression side every revolution, so a steady bending load produces a fully reversed stress. Steady torque, on the other hand, produces a mean shear stress.

What stress concentration factor should I use?

A shoulder fillet with r/d ≈ 0.1 gives Kt ≈ 1.7 in bending and 1.5 in torsion. Sharp shoulders (r/d ≈ 0.02) reach 2.7. End-milled keyways are about 2.1 bending and 3.0 torsion. Retaining ring grooves can reach 5.

What design factor is typical for shafts?

Use 1.5 to 2 for well-known loads and materials, and 2 to 3 where loads are uncertain or failure is costly. The calculator reports both fatigue and yield safety at the chosen standard diameter.

Is strength the only check?

No. Shafts often fail to function before they break: check deflection and slope at bearings and gear meshes, critical speed and key or spline strength. Stiffness frequently governs over fatigue.

What standard sizes are suggested?

The calculator rounds up to the ISO 15 bearing bore series (17, 20, 25, 30 ... mm) because the bearing seat is usually the controlling diameter.

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